16x^2-70x+76=0

Solution for 16x^2-70x+76=0 equation:

16x^2-70x+76=0

a = 16; b = -70; c = +76;
Δ = b2-4ac
Δ = -702-4·16·76
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-6}{2*16}=\frac{64}{32}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+6}{2*16}=\frac{76}{32}
=2+3/8
$